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7y+2(y-7)=5(y-1)-4
We move all terms to the left:
7y+2(y-7)-(5(y-1)-4)=0
We multiply parentheses
7y+2y-(5(y-1)-4)-14=0
We calculate terms in parentheses: -(5(y-1)-4), so:We add all the numbers together, and all the variables
5(y-1)-4
We multiply parentheses
5y-5-4
We add all the numbers together, and all the variables
5y-9
Back to the equation:
-(5y-9)
9y-(5y-9)-14=0
We get rid of parentheses
9y-5y+9-14=0
We add all the numbers together, and all the variables
4y-5=0
We move all terms containing y to the left, all other terms to the right
4y=5
y=5/4
y=1+1/4
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