7y+2(y-8)=(y+1)-4

Solution for 7y+2(y-8)=(y+1)-4 equation:

7y+2(y-8)=(y+1)-4

We move all terms to the left:

7y+2(y-8)-((y+1)-4)=0

We multiply parentheses

7y+2y-((y+1)-4)-16=0


We calculate terms in parentheses: -((y+1)-4), so:

(y+1)-4

We get rid of parentheses

y+1-4

We add all the numbers together, and all the variables

y-3

Back to the equation:

-(y-3)


We add all the numbers together, and all the variables

9y-(y-3)-16=0

We get rid of parentheses

9y-y+3-16=0

We add all the numbers together, and all the variables

8y-13=0

We move all terms containing y to the left, all other terms to the right

8y=13

y=13/8

y=1+5/8