7y+2(y-8)=4(y+2)-2

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Solution for 7y+2(y-8)=4(y+2)-2 equation: 



7y+2(y-8)=4(y+2)-2

We move all terms to the left:

7y+2(y-8)-(4(y+2)-2)=0

We multiply parentheses

7y+2y-(4(y+2)-2)-16=0



We calculate terms in parentheses: -(4(y+2)-2), so:

4(y+2)-2

We multiply parentheses

4y+8-2

We add all the numbers together, and all the variables

4y+6

Back to the equation:

-(4y+6)



We add all the numbers together, and all the variables

9y-(4y+6)-16=0

We get rid of parentheses

9y-4y-6-16=0

We add all the numbers together, and all the variables

5y-22=0

We move all terms containing y to the left, all other terms to the right

5y=22

y=22/5

y=4+2/5

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