7y+2-3(-3y-1)=4(y-1)

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Solution for 7y+2-3(-3y-1)=4(y-1) equation: 



7y+2-3(-3y-1)=4(y-1)

We move all terms to the left:

7y+2-3(-3y-1)-(4(y-1))=0

We multiply parentheses

7y+9y-(4(y-1))+3+2=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

16y-(4y-4)+5=0

We get rid of parentheses

16y-4y+4+5=0

We add all the numbers together, and all the variables

12y+9=0

We move all terms containing y to the left, all other terms to the right

12y=-9

y=-9/12

y=-3/4

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