7y+21=3(y-5)

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Solution for 7y+21=3(y-5) equation: 



7y+21=3(y-5)

We move all terms to the left:

7y+21-(3(y-5))=0



We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)



We get rid of parentheses

7y-3y+15+21=0

We add all the numbers together, and all the variables

4y+36=0

We move all terms containing y to the left, all other terms to the right

4y=-36

y=-36/4

y=-9

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