7y+29=5(y+3)

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Solution for 7y+29=5(y+3) equation: 



7y+29=5(y+3)

We move all terms to the left:

7y+29-(5(y+3))=0



We calculate terms in parentheses: -(5(y+3)), so:

5(y+3)

We multiply parentheses

5y+15

Back to the equation:

-(5y+15)



We get rid of parentheses

7y-5y-15+29=0

We add all the numbers together, and all the variables

2y+14=0

We move all terms containing y to the left, all other terms to the right

2y=-14

y=-14/2

y=-7

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