7y+3(2-y)=5(y+1)-4

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Solution for 7y+3(2-y)=5(y+1)-4 equation: 



7y+3(2-y)=5(y+1)-4

We move all terms to the left:

7y+3(2-y)-(5(y+1)-4)=0

We add all the numbers together, and all the variables

7y+3(-1y+2)-(5(y+1)-4)=0

We multiply parentheses

7y-3y-(5(y+1)-4)+6=0



We calculate terms in parentheses: -(5(y+1)-4), so:

5(y+1)-4

We multiply parentheses

5y+5-4

We add all the numbers together, and all the variables

5y+1

Back to the equation:

-(5y+1)



We add all the numbers together, and all the variables

4y-(5y+1)+6=0

We get rid of parentheses

4y-5y-1+6=0

We add all the numbers together, and all the variables

-1y+5=0

We move all terms containing y to the left, all other terms to the right

-y=-5

y=-5/-1

y=+5

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