7y+3(8-y)=12

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Solution for 7y+3(8-y)=12 equation: 



7y+3(8-y)=12

We move all terms to the left:

7y+3(8-y)-(12)=0

We add all the numbers together, and all the variables

7y+3(-1y+8)-12=0

We multiply parentheses

7y-3y+24-12=0

We add all the numbers together, and all the variables

4y+12=0

We move all terms containing y to the left, all other terms to the right

4y=-12

y=-12/4

y=-3

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