7y+3(y-2)=5(y+1)-2

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Solution for 7y+3(y-2)=5(y+1)-2 equation:



7y+3(y-2)=5(y+1)-2
We move all terms to the left:
7y+3(y-2)-(5(y+1)-2)=0
We multiply parentheses
7y+3y-(5(y+1)-2)-6=0
We calculate terms in parentheses: -(5(y+1)-2), so:
5(y+1)-2
We multiply parentheses
5y+5-2
We add all the numbers together, and all the variables
5y+3
Back to the equation:
-(5y+3)
We add all the numbers together, and all the variables
10y-(5y+3)-6=0
We get rid of parentheses
10y-5y-3-6=0
We add all the numbers together, and all the variables
5y-9=0
We move all terms containing y to the left, all other terms to the right
5y=9
y=9/5
y=1+4/5

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