7y+3(y-5)=4(y+2)-

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Solution for 7y+3(y-5)=4(y+2)- equation: 



7y+3(y-5)=4(y+2)-

We move all terms to the left:

7y+3(y-5)-(4(y+2)-)=0

We multiply parentheses

7y+3y-(4(y+2)-)-15=0



We calculate terms in parentheses: -(4(y+2)-), so:

4(y+2)-

We add all the numbers together, and all the variables

4(y+2)

We multiply parentheses

4y+8

Back to the equation:

-(4y+8)



We add all the numbers together, and all the variables

10y-(4y+8)-15=0

We get rid of parentheses

10y-4y-8-15=0

We add all the numbers together, and all the variables

6y-23=0

We move all terms containing y to the left, all other terms to the right

6y=23

y=23/6

y=3+5/6

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