7y+3(y-8)=3(y-1)-2

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Solution for 7y+3(y-8)=3(y-1)-2 equation: 



7y+3(y-8)=3(y-1)-2

We move all terms to the left:

7y+3(y-8)-(3(y-1)-2)=0

We multiply parentheses

7y+3y-(3(y-1)-2)-24=0



We calculate terms in parentheses: -(3(y-1)-2), so:

3(y-1)-2

We multiply parentheses

3y-3-2

We add all the numbers together, and all the variables

3y-5

Back to the equation:

-(3y-5)



We add all the numbers together, and all the variables

10y-(3y-5)-24=0

We get rid of parentheses

10y-3y+5-24=0

We add all the numbers together, and all the variables

7y-19=0

We move all terms containing y to the left, all other terms to the right

7y=19

y=19/7

y=2+5/7

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