7y+3y+12=32

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Solution for 7y+3y+12=32 equation: 



7y+3y+12=32

We move all terms to the left:

7y+3y+12-(32)=0

We add all the numbers together, and all the variables

10y-20=0

We move all terms containing y to the left, all other terms to the right

10y=20

y=20/10

y=2

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