7y+3y-8=5(y+2)-3

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Solution for 7y+3y-8=5(y+2)-3 equation: 



7y+3y-8=5(y+2)-3

We move all terms to the left:

7y+3y-8-(5(y+2)-3)=0

We add all the numbers together, and all the variables

10y-(5(y+2)-3)-8=0



We calculate terms in parentheses: -(5(y+2)-3), so:

5(y+2)-3

We multiply parentheses

5y+10-3

We add all the numbers together, and all the variables

5y+7

Back to the equation:

-(5y+7)



We get rid of parentheses

10y-5y-7-8=0

We add all the numbers together, and all the variables

5y-15=0

We move all terms containing y to the left, all other terms to the right

5y=15

y=15/5

y=3

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