7y+4(3+y)=100

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Solution for 7y+4(3+y)=100 equation: 



7y+4(3+y)=100

We move all terms to the left:

7y+4(3+y)-(100)=0

We add all the numbers together, and all the variables

7y+4(y+3)-100=0

We multiply parentheses

7y+4y+12-100=0

We add all the numbers together, and all the variables

11y-88=0

We move all terms containing y to the left, all other terms to the right

11y=88

y=88/11

y=8

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