7y+4(3+y)=100

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Solution for 7y+4(3+y)=100 equation:



7y+4(3+y)=100
We move all terms to the left:
7y+4(3+y)-(100)=0
We add all the numbers together, and all the variables
7y+4(y+3)-100=0
We multiply parentheses
7y+4y+12-100=0
We add all the numbers together, and all the variables
11y-88=0
We move all terms containing y to the left, all other terms to the right
11y=88
y=88/11
y=8

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