7y+4(y-8)=4(y+2)-4

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Solution for 7y+4(y-8)=4(y+2)-4 equation: 



7y+4(y-8)=4(y+2)-4

We move all terms to the left:

7y+4(y-8)-(4(y+2)-4)=0

We multiply parentheses

7y+4y-(4(y+2)-4)-32=0



We calculate terms in parentheses: -(4(y+2)-4), so:

4(y+2)-4

We multiply parentheses

4y+8-4

We add all the numbers together, and all the variables

4y+4

Back to the equation:

-(4y+4)



We add all the numbers together, and all the variables

11y-(4y+4)-32=0

We get rid of parentheses

11y-4y-4-32=0

We add all the numbers together, and all the variables

7y-36=0

We move all terms containing y to the left, all other terms to the right

7y=36

y=36/7

y=5+1/7

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