7y+43=2(2y+5)+3

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Solution for 7y+43=2(2y+5)+3 equation: 



7y+43=2(2y+5)+3

We move all terms to the left:

7y+43-(2(2y+5)+3)=0



We calculate terms in parentheses: -(2(2y+5)+3), so:

2(2y+5)+3

We multiply parentheses

4y+10+3

We add all the numbers together, and all the variables

4y+13

Back to the equation:

-(4y+13)



We get rid of parentheses

7y-4y-13+43=0

We add all the numbers together, and all the variables

3y+30=0

We move all terms containing y to the left, all other terms to the right

3y=-30

y=-30/3

y=-10

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