7y+5-11+3y-3y-5=3

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Solution for 7y+5-11+3y-3y-5=3 equation: 



7y+5-11+3y-3y-5=3

We move all terms to the left:

7y+5-11+3y-3y-5-(3)=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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