7y+6=5(y-3)

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Solution for 7y+6=5(y-3) equation: 



7y+6=5(y-3)

We move all terms to the left:

7y+6-(5(y-3))=0



We calculate terms in parentheses: -(5(y-3)), so:

5(y-3)

We multiply parentheses

5y-15

Back to the equation:

-(5y-15)



We get rid of parentheses

7y-5y+15+6=0

We add all the numbers together, and all the variables

2y+21=0

We move all terms containing y to the left, all other terms to the right

2y=-21

y=-21/2

y=-10+1/2

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