7y+7(y+3)=-35

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Solution for 7y+7(y+3)=-35 equation: 



7y+7(y+3)=-35

We move all terms to the left:

7y+7(y+3)-(-35)=0

We add all the numbers together, and all the variables

7y+7(y+3)+35=0

We multiply parentheses

7y+7y+21+35=0

We add all the numbers together, and all the variables

14y+56=0

We move all terms containing y to the left, all other terms to the right

14y=-56

y=-56/14

y=-4

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