7y+8-4(-2y-1)=3(y-2)

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Solution for 7y+8-4(-2y-1)=3(y-2) equation: 



7y+8-4(-2y-1)=3(y-2)

We move all terms to the left:

7y+8-4(-2y-1)-(3(y-2))=0

We multiply parentheses

7y+8y-(3(y-2))+4+8=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We add all the numbers together, and all the variables

15y-(3y-6)+12=0

We get rid of parentheses

15y-3y+6+12=0

We add all the numbers together, and all the variables

12y+18=0

We move all terms containing y to the left, all other terms to the right

12y=-18

y=-18/12

y=-1+1/2

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