7y+8-4(2y-1)=3(y-2)

Solution for 7y+8-4(2y-1)=3(y-2) equation:

7y+8-4(2y-1)=3(y-2)

We move all terms to the left:

7y+8-4(2y-1)-(3(y-2))=0

We multiply parentheses

7y-8y-(3(y-2))+4+8=0


We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)


We add all the numbers together, and all the variables

-1y-(3y-6)+12=0

We get rid of parentheses

-1y-3y+6+12=0

We add all the numbers together, and all the variables

-4y+18=0

We move all terms containing y to the left, all other terms to the right

-4y=-18

y=-18/-4

y=4+1/2