7y+8=2(3y+4)

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Solution for 7y+8=2(3y+4) equation: 



7y+8=2(3y+4)

We move all terms to the left:

7y+8-(2(3y+4))=0



We calculate terms in parentheses: -(2(3y+4)), so:

2(3y+4)

We multiply parentheses

6y+8

Back to the equation:

-(6y+8)



We get rid of parentheses

7y-6y-8+8=0

We add all the numbers together, and all the variables

y=0

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