7y-15=2(3y+1)+y

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Solution for 7y-15=2(3y+1)+y equation: 



7y-15=2(3y+1)+y

We move all terms to the left:

7y-15-(2(3y+1)+y)=0



We calculate terms in parentheses: -(2(3y+1)+y), so:

2(3y+1)+y

We add all the numbers together, and all the variables

y+2(3y+1)

We multiply parentheses

y+6y+2

We add all the numbers together, and all the variables

7y+2

Back to the equation:

-(7y+2)



We get rid of parentheses

7y-7y-2-15=0

We add all the numbers together, and all the variables

-17!=0

There is no solution for this equation

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