7y-1=2(y+3)+5y

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Solution for 7y-1=2(y+3)+5y equation: 



7y-1=2(y+3)+5y

We move all terms to the left:

7y-1-(2(y+3)+5y)=0



We calculate terms in parentheses: -(2(y+3)+5y), so:

2(y+3)+5y

We add all the numbers together, and all the variables

5y+2(y+3)

We multiply parentheses

5y+2y+6

We add all the numbers together, and all the variables

7y+6

Back to the equation:

-(7y+6)



We get rid of parentheses

7y-7y-6-1=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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