7y-1=2(y+3)-2*

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Solution for 7y-1=2(y+3)-2* equation: 



7y-1=2(y+3)-2*

We move all terms to the left:

7y-1-(2(y+3)-2*)=0



We calculate terms in parentheses: -(2(y+3)-2*), so:

2(y+3)-2*

We add all the numbers together, and all the variables

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

7y-2y-6-1=0

We add all the numbers together, and all the variables

5y-7=0

We move all terms containing y to the left, all other terms to the right

5y=7

y=7/5

y=1+2/5

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