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7y-2(5=3y/2)=5y-17
We move all terms to the left:
7y-2(5-(3y/2))=0
We add all the numbers together, and all the variables
7y-2(5-(+3y/2))=0
We multiply all the terms by the denominator
7y*2))-2(5-(+3y=0
We add all the numbers together, and all the variables
3y+7y*2))-2(5-(=0
Wy multiply elements
14y^2+3y=0
a = 14; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·14·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*14}=\frac{-6}{28} =-3/14 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*14}=\frac{0}{28} =0 $
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