7y-2(y-8)=4(y+1)-3

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Solution for 7y-2(y-8)=4(y+1)-3 equation: 


Simplifying
7y + -2(y + -8) = 4(y + 1) + -3

Reorder the terms:
7y + -2(-8 + y) = 4(y + 1) + -3
7y + (-8 * -2 + y * -2) = 4(y + 1) + -3
7y + (16 + -2y) = 4(y + 1) + -3

Reorder the terms:
16 + 7y + -2y = 4(y + 1) + -3

Combine like terms: 7y + -2y = 5y
16 + 5y = 4(y + 1) + -3

Reorder the terms:
16 + 5y = 4(1 + y) + -3
16 + 5y = (1 * 4 + y * 4) + -3
16 + 5y = (4 + 4y) + -3

Reorder the terms:
16 + 5y = 4 + -3 + 4y

Combine like terms: 4 + -3 = 1
16 + 5y = 1 + 4y

Solving
16 + 5y = 1 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
16 + 5y + -4y = 1 + 4y + -4y

Combine like terms: 5y + -4y = 1y
16 + 1y = 1 + 4y + -4y

Combine like terms: 4y + -4y = 0
16 + 1y = 1 + 0
16 + 1y = 1

Add '-16' to each side of the equation.
16 + -16 + 1y = 1 + -16

Combine like terms: 16 + -16 = 0
0 + 1y = 1 + -16
1y = 1 + -16

Combine like terms: 1 + -16 = -15
1y = -15

Divide each side by '1'.
y = -15

Simplifying
y = -15

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