7y-2(y-9)=10y-(6y+12)

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Solution for 7y-2(y-9)=10y-(6y+12) equation: 



7y-2(y-9)=10y-(6y+12)

We move all terms to the left:

7y-2(y-9)-(10y-(6y+12))=0

We multiply parentheses

7y-2y-(10y-(6y+12))+18=0



We calculate terms in parentheses: -(10y-(6y+12)), so:

10y-(6y+12)

We get rid of parentheses

10y-6y-12

We add all the numbers together, and all the variables

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

5y-(4y-12)+18=0

We get rid of parentheses

5y-4y+12+18=0

We add all the numbers together, and all the variables

y+30=0

We move all terms containing y to the left, all other terms to the right

y=-30

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