7y-3(2y-5)+5+3y=4y+20

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Solution for 7y-3(2y-5)+5+3y=4y+20 equation: 


Simplifying
7y + -3(2y + -5) + 5 + 3y = 4y + 20

Reorder the terms:
7y + -3(-5 + 2y) + 5 + 3y = 4y + 20
7y + (-5 * -3 + 2y * -3) + 5 + 3y = 4y + 20
7y + (15 + -6y) + 5 + 3y = 4y + 20

Reorder the terms:
15 + 5 + 7y + -6y + 3y = 4y + 20

Combine like terms: 15 + 5 = 20
20 + 7y + -6y + 3y = 4y + 20

Combine like terms: 7y + -6y = 1y
20 + 1y + 3y = 4y + 20

Combine like terms: 1y + 3y = 4y
20 + 4y = 4y + 20

Reorder the terms:
20 + 4y = 20 + 4y

Add '-20' to each side of the equation.
20 + -20 + 4y = 20 + -20 + 4y

Combine like terms: 20 + -20 = 0
0 + 4y = 20 + -20 + 4y
4y = 20 + -20 + 4y

Combine like terms: 20 + -20 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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