7y-31=2(y-2)

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Solution for 7y-31=2(y-2) equation: 



7y-31=2(y-2)

We move all terms to the left:

7y-31-(2(y-2))=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

7y-2y+4-31=0

We add all the numbers together, and all the variables

5y-27=0

We move all terms containing y to the left, all other terms to the right

5y=27

y=27/5

y=5+2/5

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