If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7y-32=-5(y+4)
We move all terms to the left:
7y-32-(-5(y+4))=0
We calculate terms in parentheses: -(-5(y+4)), so:We get rid of parentheses
-5(y+4)
We multiply parentheses
-5y-20
Back to the equation:
-(-5y-20)
7y+5y+20-32=0
We add all the numbers together, and all the variables
12y-12=0
We move all terms containing y to the left, all other terms to the right
12y=12
y=12/12
y=1
| w+4=17 | | 30=2(u-5)-6u | | 7-y/5=3/; | | w−–4=17 | | -10=-1+p | | 10.5-5x=2x | | 3(x−4)^2=18 | | 3(x−4)2=18 | | 2x=105x-8 | | 2^(2x+2)10^(x+1)-10*2^(3x)5^(x)=1200 | | ((x*0,1)+x)=110 | | x*0,1+x=110 | | x*0,1+x=110 | | 14x=12600 | | 14x=12600 | | 3-5x=2x-3 | | --5y+8=7 | | --5y+8=7 | | 12.x=18 | | x10+31=98 | | 5/x=45/63 | | x-4=5(2(x+8) | | 5=4d-15 | | 7a+a=3a | | 36x2–12x–15=0 | | 23=m-24 | | 5d+2(2-d)=3(1+d)+4 | | 5d+2(2-d)=3(1+d)+4 | | 5d+2(2-d)=3(1+d)+4 | | 5d+2(2-d)=3(1+d)+4 | | 5d+2(2-d)=3(1+d)+4 | | 5d+2(2-d)=3(1+d)+4 |