7y-33=-3(y+1)

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Solution for 7y-33=-3(y+1) equation: 



7y-33=-3(y+1)

We move all terms to the left:

7y-33-(-3(y+1))=0



We calculate terms in parentheses: -(-3(y+1)), so:

-3(y+1)

We multiply parentheses

-3y-3

Back to the equation:

-(-3y-3)



We get rid of parentheses

7y+3y+3-33=0

We add all the numbers together, and all the variables

10y-30=0

We move all terms containing y to the left, all other terms to the right

10y=30

y=30/10

y=3

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