7y-33=4(y-3)

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Solution for 7y-33=4(y-3) equation: 



7y-33=4(y-3)

We move all terms to the left:

7y-33-(4(y-3))=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We get rid of parentheses

7y-4y+12-33=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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