7y-35+3y=10(y+1)

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Solution for 7y-35+3y=10(y+1) equation: 



7y-35+3y=10(y+1)

We move all terms to the left:

7y-35+3y-(10(y+1))=0

We add all the numbers together, and all the variables

10y-(10(y+1))-35=0



We calculate terms in parentheses: -(10(y+1)), so:

10(y+1)

We multiply parentheses

10y+10

Back to the equation:

-(10y+10)



We get rid of parentheses

10y-10y-10-35=0

We add all the numbers together, and all the variables

-45!=0

There is no solution for this equation

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