7y-36=3(y-4)

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Solution for 7y-36=3(y-4) equation: 



7y-36=3(y-4)

We move all terms to the left:

7y-36-(3(y-4))=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We get rid of parentheses

7y-3y+12-36=0

We add all the numbers together, and all the variables

4y-24=0

We move all terms containing y to the left, all other terms to the right

4y=24

y=24/4

y=6

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