7y-3=2(5y-2)+6

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Solution for 7y-3=2(5y-2)+6 equation: 



7y-3=2(5y-2)+6

We move all terms to the left:

7y-3-(2(5y-2)+6)=0



We calculate terms in parentheses: -(2(5y-2)+6), so:

2(5y-2)+6

We multiply parentheses

10y-4+6

We add all the numbers together, and all the variables

10y+2

Back to the equation:

-(10y+2)



We get rid of parentheses

7y-10y-2-3=0

We add all the numbers together, and all the variables

-3y-5=0

We move all terms containing y to the left, all other terms to the right

-3y=5

y=5/-3

y=-1+2/3

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