7y-3=2(5y-2)+6

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Solution for 7y-3=2(5y-2)+6 equation:



7y-3=2(5y-2)+6
We move all terms to the left:
7y-3-(2(5y-2)+6)=0
We calculate terms in parentheses: -(2(5y-2)+6), so:
2(5y-2)+6
We multiply parentheses
10y-4+6
We add all the numbers together, and all the variables
10y+2
Back to the equation:
-(10y+2)
We get rid of parentheses
7y-10y-2-3=0
We add all the numbers together, and all the variables
-3y-5=0
We move all terms containing y to the left, all other terms to the right
-3y=5
y=5/-3
y=-1+2/3

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