7y-4(3-5)=80

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Solution for 7y-4(3-5)=80 equation: 



7y-4(3-5)=80

We move all terms to the left:

7y-4(3-5)-(80)=0

determiningTheFunctionDomain
7y-80-4(3-5)=0

We add all the numbers together, and all the variables

7y-80-4(-2)=0

We add all the numbers together, and all the variables

7y-72=0

We move all terms containing y to the left, all other terms to the right

7y=72

y=72/7

y=10+2/7

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