7y-4+(y+5)=28

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Solution for 7y-4+(y+5)=28 equation: 



7y-4+(y+5)=28

We move all terms to the left:

7y-4+(y+5)-(28)=0

We add all the numbers together, and all the variables

7y+(y+5)-32=0

We get rid of parentheses

7y+y+5-32=0

We add all the numbers together, and all the variables

8y-27=0

We move all terms containing y to the left, all other terms to the right

8y=27

y=27/8

y=3+3/8

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