7y-40=28+3y

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Solution for 7y-40=28+3y equation: 



7y-40=28+3y

We move all terms to the left:

7y-40-(28+3y)=0

We add all the numbers together, and all the variables

7y-(3y+28)-40=0

We get rid of parentheses

7y-3y-28-40=0

We add all the numbers together, and all the variables

4y-68=0

We move all terms containing y to the left, all other terms to the right

4y=68

y=68/4

y=17

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