7y-40=48+3y

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Solution for 7y-40=48+3y equation: 



7y-40=48+3y

We move all terms to the left:

7y-40-(48+3y)=0

We add all the numbers together, and all the variables

7y-(3y+48)-40=0

We get rid of parentheses

7y-3y-48-40=0

We add all the numbers together, and all the variables

4y-88=0

We move all terms containing y to the left, all other terms to the right

4y=88

y=88/4

y=22

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