7y-4=3(y+12)

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Solution for 7y-4=3(y+12) equation:



7y-4=3(y+12)
We move all terms to the left:
7y-4-(3(y+12))=0
We calculate terms in parentheses: -(3(y+12)), so:
3(y+12)
We multiply parentheses
3y+36
Back to the equation:
-(3y+36)
We get rid of parentheses
7y-3y-36-4=0
We add all the numbers together, and all the variables
4y-40=0
We move all terms containing y to the left, all other terms to the right
4y=40
y=40/4
y=10

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