7y-56+24=3y-(-18)

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Solution for 7y-56+24=3y-(-18) equation: 



7y-56+24=3y-(-18)

We move all terms to the left:

7y-56+24-(3y-(-18))=0

We add all the numbers together, and all the variables

7y-(3y-(-18))-32=0



We calculate terms in parentheses: -(3y-(-18)), so:

3y-(-18)

We add all the numbers together, and all the variables

3y+18

Back to the equation:

-(3y+18)



We get rid of parentheses

7y-3y-18-32=0

We add all the numbers together, and all the variables

4y-50=0

We move all terms containing y to the left, all other terms to the right

4y=50

y=50/4

y=12+1/2

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