7y-8+3(2y+1)=-2(y+1)

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Solution for 7y-8+3(2y+1)=-2(y+1) equation: 



7y-8+3(2y+1)=-2(y+1)

We move all terms to the left:

7y-8+3(2y+1)-(-2(y+1))=0

We multiply parentheses

7y+6y-(-2(y+1))+3-8=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

13y-(-2y-2)-5=0

We get rid of parentheses

13y+2y+2-5=0

We add all the numbers together, and all the variables

15y-3=0

We move all terms containing y to the left, all other terms to the right

15y=3

y=3/15

y=1/5

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