7y2+0.12=1.24

Solution for 7y2+0.12=1.24 equation:

7y^2+0.12=1.24

We move all terms to the left:

7y^2+0.12-(1.24)=0

We add all the numbers together, and all the variables

7y^2-1.12=0

a = 7; b = 0; c = -1.12;
Δ = b2-4ac
Δ = 02-4·7·(-1.12)
Δ = 31.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{31.36}}{2*7}=\frac{0-\sqrt{31.36}}{14}
=-\frac{\sqrt{}}{14}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{31.36}}{2*7}=\frac{0+\sqrt{31.36}}{14}
=\frac{\sqrt{}}{14}
$