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7y^2+1=3y-2
We move all terms to the left:
7y^2+1-(3y-2)=0
We get rid of parentheses
7y^2-3y+2+1=0
We add all the numbers together, and all the variables
7y^2-3y+3=0
a = 7; b = -3; c = +3;
Δ = b2-4ac
Δ = -32-4·7·3
Δ = -75
Delta is less than zero, so there is no solution for the equation
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