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7y^2-22y+16=0
a = 7; b = -22; c = +16;
Δ = b2-4ac
Δ = -222-4·7·16
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-6}{2*7}=\frac{16}{14} =1+1/7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+6}{2*7}=\frac{28}{14} =2 $
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