7y2=y=5

Solution for 7y2=y=5 equation:

7y^2=y=5

We move all terms to the left:

7y^2-(y)=0

We add all the numbers together, and all the variables

7y^2-1y=0

a = 7; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·7·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*7}=\frac{0}{14}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*7}=\frac{2}{14}
=1/7
$