7y=(5y+28)

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Solution for 7y=(5y+28) equation: 



7y=(5y+28)

We move all terms to the left:

7y-((5y+28))=0



We calculate terms in parentheses: -((5y+28)), so:

(5y+28)

We get rid of parentheses

5y+28

Back to the equation:

-(5y+28)



We get rid of parentheses

7y-5y-28=0

We add all the numbers together, and all the variables

2y-28=0

We move all terms containing y to the left, all other terms to the right

2y=28

y=28/2

y=14

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