7z+10-2=8z-2(2-5)

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Solution for 7z+10-2=8z-2(2-5) equation: 



7z+10-2=8z-2(2-5)

We move all terms to the left:

7z+10-2-(8z-2(2-5))=0

We add all the numbers together, and all the variables

7z-(8z-2(-3))+10-2=0

We add all the numbers together, and all the variables

7z-(8z-2(-3))+8=0



We calculate terms in parentheses: -(8z-2(-3)), so:

8z-2(-3)

We add all the numbers together, and all the variables

8z+6

Back to the equation:

-(8z+6)



We get rid of parentheses

7z-8z-6+8=0

We add all the numbers together, and all the variables

-1z+2=0

We move all terms containing z to the left, all other terms to the right

-z=-2

z=-2/-1

z=+2

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