7z+15=32

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Solution for 7z+15=32 equation: 



7z+15=32

We move all terms to the left:

7z+15-(32)=0

We add all the numbers together, and all the variables

7z-17=0

We move all terms containing z to the left, all other terms to the right

7z=17

z=17/7

z=2+3/7

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